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MHT CET 2024 (4 May, Shift 1) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2024 (4 May, Shift 1)

Q51MHT CET 2024 · 4 MAY · SHIFT 1Medium

Stationary Waves & Vibrating Strings

A string A has twice the length, twice the diameter, twice the tension and twice the density of another string B. The overtone of A which will have the same fundamental frequency as that of BB is

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Answer: (c)

  1. n∝1LDTρn \propto \dfrac{1}{LD}\sqrt{\dfrac{T}{\rho}}
  2. nAnB=12×222=14⇒nB=4nA\dfrac{n_A}{n_B} = \dfrac{1}{2\times2}\sqrt{\dfrac{2}{2}} = \dfrac{1}{4} \Rightarrow n_B = 4n_A
  3. The 4th harmonic of A equals nBn_B; the 4th harmonic is the third overtone.
  4. So the answer is (c) third.
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