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MHT CET 2024 (15 May, Shift 2) · Progressive Wave Equation

Progressive Wave Equation question from MHT CET 2024 (15 May, Shift 2)

Q47MHT CET 2024 · 15 MAY · SHIFT 2Medium

Progressive Wave Equation

A string has mass per unit length of 10−6 kg/cm10^{-6}\text{ kg/cm} The equation of simple harmonic wave produced in it is Y=0.2sin⁡(2x+80t) mY = 0.2\sin(2x + 80t)\text{ m}. The tension in the string is

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Answer: (a)

  1. μ=10−6 kg/cm=10−4 kg/m\mu = 10^{-6}\text{ kg/cm} = 10^{-4}\text{ kg/m}
  2. v=ωk=802=40 m/sv = \frac{\omega}{k} = \frac{80}{2} = 40\text{ m/s}
  3. T=μv2=10−4×1600=0.16 NT = \mu v^2 = 10^{-4} \times 1600 = 0.16\text{ N}
  4. So the answer is (a) 0.16 N.
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