A string is stretched between two rigid supports separated by 75 cm. There are no resonant frequencies between 420 Hz and 315 Hz. The lowest resonant frequency for the string is (a) 210 Hz (b) 180 Hz (c) 105 Hz (d) 1050 Hz

Answer: (c). No resonance between them, so 315 Hz and 420 Hz are consecutive harmonics. Difference of consecutive harmonics = fundamental: n₁ = 420 - 315 = 105 Hz. So the answer is (c) 105 Hz.

A string is stretched between two rigid supports separated by 75 cm… | MHT CET 2023 (14 May, Shift 1)

Q63MHT CET 2023 · 14 MAY · SHIFT 1Medium

Stationary Waves & Vibrating Strings

A string is stretched between two rigid supports separated by $75\text{ cm}$ . There are no resonant frequencies between $420\text{ Hz}$ and $315\text{ Hz}$ . The lowest resonant frequency for the string is

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Answer: (c)

No resonance between them, so 315 Hz and 420 Hz are consecutive harmonics.
Difference of consecutive harmonics = fundamental: $n_1 = 420 - 315 = 105\text{ Hz}$ .
So the answer is (c) $105\text{ Hz}$ .

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