A string of length 'L' fixed at one end carries a mass 'm' at the other end. The string makes 3/π r.p.s. π around the vertical axis through fixed end. The tension in the string is (a) 72mL (b) 36mL (c) 18mL (d) 9mL

Answer: (b). ω = 2π n = 2π × 3/π = 6 rad/s Conical pendulum: Tsin θ = mω² (Lsin θ) ⇒ T = mω² L. T = 36 mL So the answer is (b) 36mL.

A string of length 'L' fixed at one end carries a mass 'm' at the… | MHT CET 2026 (13 Apr, Shift 1)

Q1MHT CET 2026 · 13 APR · SHIFT 1Easy

Conical Pendulum & Funnel

A string of length 'L' fixed at one end carries a mass 'm' at the other end. The string makes $\frac{3}{\pi}$ r.p.s. $\pi$ around the vertical axis through fixed end. The tension in the string is

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Answer: (b)

$\omega = 2\pi n = 2\pi \times \frac{3}{\pi} = 6$ rad/s
Conical pendulum: $T\sin\theta = m\omega^2 (L\sin\theta) \Rightarrow T = m\omega^2 L$ .
$T = 36\,mL$
So the answer is (b) $36mL$ .

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