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JEE Main 2025 (24 Jan, Shift 2) · Conical Pendulum & Funnel

Conical Pendulum & Funnel question from JEE Main 2025 (24 Jan, Shift 2)

Q5JEE Main 2025 · 24 JAN · SHIFT 2Medium

Conical Pendulum & Funnel

Figure

A string of length LL is fixed at one end and carries a mass of MM at the other end. The mass makes (3π)\left(\frac{3}{\pi}\right) rotations per second about the vertical axis passing through end of the string as shown. The tension in the string is __________ ML.

Numerical answer type. Work it out, then open the answer.

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Answer: 36

  1. ω=2πn=2π×3π=6\omega = 2\pi n = 2\pi \times \frac{3}{\pi} = 6 rad/s
  2. Tsin⁡θ=Mω2(Lsin⁡θ)⇒T=Mω2LT\sin\theta = M\omega^2 (L\sin\theta) \Rightarrow T = M\omega^2 L
  3. T=36 MLT = 36\,ML
  4. So the answer is 36.
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