A student is performing the experiment of resonance column. The… | JEE Main 2021 (25 Feb, Shift 1)

Q89JEE Main 2021 · 25 FEB · SHIFT 1Medium

Organ Pipes & Resonance Tube

A student is performing the experiment of resonance column. The diameter of the column tube is 6 cm. The frequency of the tuning fork is 504 Hz. Speed of the sound at the given temperature is 336 m/s. The zero of the metre scale coincides with the top end of the resonance column tube. The reading of the water level in the column when the first resonance occurs is:

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Answer: (d)

$\lambda = \frac{336}{504} = 0.667$ m, so $\frac{\lambda}{4} = 16.67$ cm.
End correction $e = 0.3d = 0.3 \times 6 = 1.8$ cm.
First resonance: $l_1 = \frac{\lambda}{4} - e = 16.67 - 1.8 \approx 14.8$ cm
So the answer is (d) 14.8 cm.

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