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JEE Main 2008 (AIEEE) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from JEE Main 2008 (AIEEE)

Q106JEE Main 2008 · AIEEEMedium

Spherical Surfaces & Thin Lenses

A student measures the focal length of a convex lens by putting an object pin at a distance ′u′'u' from the lens and measuring the distance ′v′'v' of the image pin. The graph between ′u′'u' and ′v′'v' plotted by the student should look like

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Answer: (c)

  1. Real-is-positive convention: uu is negative and vv positive, so the graph lies in the second quadrant.
  2. 1v−1u=1f\frac{1}{v} - \frac{1}{u} = \frac{1}{f}: as ∣u∣→f|u| \to f, v→∞v \to \infty; as ∣u∣→∞|u| \to \infty, v→fv \to f.
  3. This is a rectangular-hyperbola-like curve in the second quadrant.
  4. So the answer is (c).
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