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NEET 2009 (AIPMT) · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from NEET 2009 (AIPMT)

Q45NEET 2009 · AIPMTEasy

Cells: EMF, Internal Resistance & Combinations

A student measures the terminal potential difference (V) of a cell (of emf $\varepsilon$ and internal resistance r) as a function of the current (I) flowing through it. The slope, and intercept, of the graph between V and I, then respectively, equal

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Answer: (a)

$V = \varepsilon - Ir$ , i.e. $V = (-r)I + \varepsilon$ , a straight line.
Compare with $y = mx + c$ : slope $= -r$ , intercept $= \varepsilon$ .
So the answer is (a) $-r$ and $\varepsilon$ .

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