Distance, Displacement & Average Speed question from MHT CET 2026 (15 May, Shift 2)

Answer: (a)

1. Radius $R = 80/2 = 40$ m.
2. Distance $= \frac{3}{4}(2\pi R) = \frac{3}{4}(80\pi) = 60\pi$ m.
3. After $\frac{3}{4}$ turn the angle swept is $270^\circ$, so start and end radii are perpendicular: displacement $= \sqrt{R^2 + R^2} = R\sqrt{2} = 40\sqrt{2}$ m.
4. So the answer is (a) $60\pi, 40\sqrt{2}$.