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JEE Main 2025 (23 Jan, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2025 (23 Jan, Shift 1)

Q33JEE Main 2025 · 23 JAN · SHIFT 1Medium

Matter Waves: de Broglie Wavelength

A sub-atomic particle of mass 10−30 kg10^{-30}\text{ kg} is moving with a velocity 2.21×106 m/s2.21 \times 10^{6}\text{ m/s}. Under the matter wave consideration, the particle will behave closely like (h=6.63×10−34 J s)(\mathrm{h} = 6.63 \times 10^{-34}\text{ J s})

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Answer: (a)

  1. λ=hmv=6.63×10−3410−30×2.21×106\lambda = \dfrac{h}{mv} = \dfrac{6.63 \times 10^{-34}}{10^{-30} \times 2.21 \times 10^{6}}
  2. λ=3×10−10 m=3 A˚\lambda = 3 \times 10^{-10}\text{ m} = 3\text{ Å}
  3. Wavelengths of a few Å lie in the X-ray region.
  4. So the answer is (a) X-rays.
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