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NEET 2014 (AIPMT) · Friction Basics

Friction Basics question from NEET 2014 (AIPMT)

Q27NEET 2014 · AIPMTMedium

Friction Basics

A system consists of three masses m1, m2 and m3 connected by a string passing over a pulley P. The mass m1 hangs freely and m2 and m3 are on a rough horizontal table (the coefficient of friction = μ\mu). The pulley is frictionless and of negligible mass. The downward acceleration of mass m1 is (Assume m1 = m2 = m3 = m)

Figure

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Answer: (c)

  1. Driving force =m1g=mg= m_1 g = mg; friction on m2m_2 and m3m_3 =μ(2m)g= \mu(2m)g.
  2. Total moving mass =3m= 3m.
  3. a=mg−2μmg3ma = \dfrac{mg - 2\mu mg}{3m}
  4. So the answer is (c) g(1−2μ)3\dfrac{g(1-2\mu)}{3}.
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