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P-V Diagrams & Cyclic Processes question from NEET 2013

Q76NEET 2013Medium

P-V Diagrams & Cyclic Processes

A system is taken from state a to state c by two paths adc and abc as shown in the figure. The internal energy at a is Ua=10 JU_a = 10\text{ J}. Along the path adc the amount of heat absorbed dQ1 == 50 J and the work obtained dW1 == 20 J whereas along the path abc the heat absorbed dQ2 = 36 J. The amount of work along the path abc is

Figure

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Answer: (d)

  1. Path adc: ΔU=Q1−W1=50−20=30 J\Delta U = Q_1 - W_1 = 50 - 20 = 30\ \text{J}.
  2. Same ΔU\Delta U for path abc: W2=Q2−ΔU=36−30=6 JW_2 = Q_2 - \Delta U = 36 - 30 = 6\ \text{J}
  3. So the answer is (d) 6 J.
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