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JEE Main 2019 (12 Apr, Shift 2) · Polarisation

Polarisation question from JEE Main 2019 (12 Apr, Shift 2)

Q50JEE Main 2019 · 12 APR · SHIFT 2Medium

Polarisation

A system of three polarizers P1, P2, P3 is set up such that the pass axis of P3 is crossed with respect to that of P1. The pass axis of P2 is inclined at 60° to the pass axis of P3. When a beam of unpolarized light of intensity I0 is incident on P1, the intensity of light transmitted by the three polarizers is I. The ratio ( I0I\frac{I_0}{I}) equals (nearly):

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Answer: (a)

  1. P3P_3 is crossed with P1P_1 and P2P_2 is at 60∘60^\circ to P3P_3, so P2P_2 is at 30∘30^\circ to P1P_1.
  2. I=I02cos⁡230∘cos⁡260∘=I02⋅34⋅14=3I032I = \frac{I_0}{2}\cos^2 30^\circ\cos^2 60^\circ = \frac{I_0}{2}\cdot\frac{3}{4}\cdot\frac{1}{4} = \frac{3I_0}{32}
  3. I0I=323≈10.67\frac{I_0}{I} = \frac{32}{3} \approx 10.67
  4. So the answer is (a) 10.67.
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