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JEE Main 2022 (27 Jun, Shift 1) · Two-Body Friction

Two-Body Friction question from JEE Main 2022 (27 Jun, Shift 1)

Q3JEE Main 2022 · 27 JUN · SHIFT 1Easy

Two-Body Friction

A system of two blocks of masses m = 2 kg and M = 8 kg is placed on a smooth table as shown in figure. The coefficient of static friction between two blocks is 0.5. The maximum horizontal force F that can be applied to the block of mass M so that the blocks move together will be:

Figure

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Answer: (c)

  1. Only friction accelerates m, so its maximum acceleration is a=μsg=0.5×9.8=4.9a = \mu_s g = 0.5 \times 9.8 = 4.9 m/s2^2.
  2. Both move together with this aa: F=(M+m)a=10×4.9F = (M+m)a = 10 \times 4.9
  3. F=49F = 49 N, so the answer is (c).
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