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NEET 2004 (AIPMT) · Resolving Power

Resolving Power question from NEET 2004 (AIPMT)

Q26NEET 2004 · AIPMTMedium

Resolving Power

A telescope has an objective lens of 10 cm diameter and is situated at a distance of one kilometer from two objects. The minimum distance between these two objects, which can be resolved by the telescope, when the mean wavelength of light is 5000 A˚\text{Å}, is of the order of

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Answer: (c)

  1. θ=1.22λD=1.22×5×10−70.1=6.1×10−6\theta = \dfrac{1.22\lambda}{D} = \dfrac{1.22\times5\times10^{-7}}{0.1} = 6.1\times10^{-6} rad
  2. Minimum separation x=Lθ=1000×6.1×10−6=6.1×10−3x = L\theta = 1000 \times 6.1\times10^{-6} = 6.1\times10^{-3} m
  3. This is of the order of a few mm.
  4. So the answer is (c) 5 mm.
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