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NEET 2012 (AIPMT, Prelims) · P-V Diagrams & Cyclic Processes

P-V Diagrams & Cyclic Processes question from NEET 2012 (AIPMT, Prelims)

Q83NEET 2012 · AIPMT · PRELIMSMedium

P-V Diagrams & Cyclic Processes

A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is

Figure

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Answer: (a)

  1. Area enclosed =(2P−P)(3V−V)=2PV= (2P - P)(3V - V) = 2PV.
  2. A to B (rightwards at PP), B to C (up), C to D (leftwards at 2P2P) is anticlockwise, so W=−2PVW = -2PV.
  3. For a cycle Q=W=−2PVQ = W = -2PV: the gas rejects heat 2PV2PV.
  4. So the answer is (a) 2PV.
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