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JEE Main 2006 (AIEEE) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from JEE Main 2006 (AIEEE)

Q90JEE Main 2006 · AIEEEMedium

Angular Momentum & its Conservation

A thin circular ring of mass $m$ and radius $R$ is rotating about its axis with a constant angular velocity $\omega$ . Two objects each of mass $M$ are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with an angular velocity $\omega' =$

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Answer: (d)

Conservation of $L$ : $mR^2\omega = (m+2M)R^2\omega'$ .
$\omega' = \frac{\omega m}{m+2M}$
So the answer is (d) $\frac{\omega m}{(m+2M)}$ .

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