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JEE Main 2022 (26 Jun, Shift 1) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from JEE Main 2022 (26 Jun, Shift 1)

Q43JEE Main 2022 · 26 JUN · SHIFT 1Medium

Angular Momentum & its Conservation

A thin circular ring of mass M and radius R is rotating with a constant angular velocity 2 rads−1{}^{-1} in a horizontal plane about an axis vertical to its plane and passing through the center of the ring. If two objects each of mass m be attached gently to the opposite ends of a diameter of ring, the ring will then rotate with an angular velocity (in rads−1{}^{-1}).

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Answer: (c)

  1. Conservation of LL: MR2(2)=(M+2m)R2ω′MR^2(2) = (M+2m)R^2\omega'.
  2. ω′=2MM+2m rad s−1\omega' = \frac{2M}{M+2m}\ \text{rad s}^{-1}
  3. So the answer is (c) 2M(M+2m)\frac{2M}{(M+2m)}.
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