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NEET 1998 (AIPMT) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from NEET 1998 (AIPMT)

Q97NEET 1998 · AIPMTMedium

Angular Momentum & its Conservation

A thin circular ring of mass $M$ and radius $r$ is rotating about its axis with a constant angular velocity $\omega$ . Two objects each of mass $m$ are attached gently to the opposite ends of diameter of the ring. The ring will now rotate with an angular velocity

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Answer: (b)

Conservation of $L$ : $Mr^2\omega = (M+2m)r^2\omega'$ .
$\omega' = \frac{\omega M}{M+2m}$
So the answer is (b) $\frac{\omega M}{(M+2m)}$ .

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