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NEET 2003 (AIPMT) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from NEET 2003 (AIPMT)

Q93NEET 2003 · AIPMTMedium

Angular Momentum & its Conservation

A thin circular ring of mass M and radius r is rotating about its axis with a constant angular velocity $\omega$ . Four objects each of mass m, are kept gently to the opposite ends of two perpendicular diameters of the ring. The angular velocity of the ring will be:

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Answer: (b)

Four masses on the rim add $4mr^2$ : $I' = (M+4m)r^2$ .
Conservation of $L$ : $Mr^2\omega = (M+4m)r^2\omega'$ .
$\omega' = \frac{M\omega}{M+4m}$
So the answer is (b) $\frac{M\omega}{M+4m}$ .

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