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NEET 2010 (AIPMT, Mains) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from NEET 2010 (AIPMT, Mains)

Q85NEET 2010 · AIPMT · MAINSMedium

Angular Momentum & its Conservation

A thin circular ring of mass M and radius r is rotating about its axis with constant angular velocity ω\omega. Two objects each of mass m are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity given by

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Answer: (d)

  1. Conservation of LL: I1ω=I2ω′I_1\omega = I_2\omega'.
  2. I1=Mr2I_1 = Mr^2, I2=Mr2+2mr2=(M+2m)r2I_2 = Mr^2 + 2mr^2 = (M+2m)r^2.
  3. ω′=MωM+2m\omega' = \frac{M\omega}{M+2m}
  4. So the answer is (d) MωM+2m\frac{M\omega}{M+2m}.
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