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NEET 2008 (AIPMT) · Electric Field & Field Lines

Electric Field & Field Lines question from NEET 2008 (AIPMT)

Q48NEET 2008 · AIPMTMedium

Electric Field & Field Lines

A thin conducting ring of radius R is given a charge +Q. The electric field at the centre O of the ring due to the charge on the part AKB of the ring is E. The electric field at the centre due to the charge on the part ACDB of the ring is

Figure

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Answer: (d)

  1. A complete uniformly charged ring gives zero field at its centre: E⃗AKB+E⃗ACDB=0\vec E_{AKB} + \vec E_{ACDB} = 0.
  2. Charge on AKB is positive, so its field at O points away from K, i.e. along KO, with magnitude EE.
  3. Hence E⃗ACDB=−E⃗AKB\vec E_{ACDB} = -\vec E_{AKB}: magnitude EE, directed along OK.
  4. So the answer is (d) E along OK.
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