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MHT CET 2026 (20 Apr, Shift 2) · Prism, Dispersion & Scattering

Prism, Dispersion & Scattering question from MHT CET 2026 (20 Apr, Shift 2)

Q3MHT CET 2026 · 20 APR · SHIFT 2Easy

Prism, Dispersion & Scattering

A thin glass prism has refractive index $1.5$ . The correct relation between the angle of minimum deviation $(\delta_m)$ and angle of refraction $(r)$ is

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Answer: (c)

Thin prism: $\delta_m = (\mu - 1)A = (1.5 - 1)A = \frac{A}{2}$ .
At minimum deviation $r = \frac{A}{2}$ .
So $\delta_m = r$ , the answer is (c).

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