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JEE Main 2005 (AIEEE) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from JEE Main 2005 (AIEEE)

Q107JEE Main 2005 · AIEEEEasy

Spherical Surfaces & Thin Lenses

A thin glass (refractive index 1.51.5) lens has optical power of −5 D-5\ D in air. Its optical power in a liquid medium with refractive index 1.61.6 will be

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Answer: (b)

  1. Power in a medium of index nn: P=nfP = \frac{n}{f}, with 1f=(μn−1)(1R1−1R2)\frac{1}{f} = \left(\frac{\mu}{n} - 1\right)\left(\frac{1}{R_1} - \frac{1}{R_2}\right).
  2. In air: −5=(1.5−1)K⇒K=(1R1−1R2)=−10 m−1-5 = (1.5 - 1)K \Rightarrow K = \left(\frac{1}{R_1} - \frac{1}{R_2}\right) = -10\text{ m}^{-1}
  3. In liquid: 1f=(1.51.6−1)(−10)=0.625 m−1\frac{1}{f} = \left(\frac{1.5}{1.6} - 1\right)(-10) = 0.625\text{ m}^{-1}
  4. P=1.6×0.625=+1 DP = 1.6 \times 0.625 = +1\text{ D}
  5. So the answer is (b) 1 D1\ D.
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