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NEET 2026 (Re-neet) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from NEET 2026 (Re-neet)

Q7NEET 2026 · RE-NEETMedium

Angular Momentum & its Conservation

A thin horizontal disc is rotating about a vertical axis passing through its fixed centre $O$ . Its angular momentum is $L_A$ and $L_B$ computed about points $A$ and $B$ , respectively, with $OB = 2 \times OA$ . The value of $\frac{L_A}{L_B}$ is:

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Answer: (d)

$\vec L_P=\vec L_{cm}+M\,\vec r_{cm}\times\vec v_{cm}$ about any point P.
The centre O is fixed, so $\vec v_{cm}=0$ and $\vec L_A=\vec L_B=I\omega$ .
$\frac{L_A}{L_B}=1$
So the answer is (d) 1.

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