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JEE Main 2012 (AIEEE) · Force due to Surface Tension

Force due to Surface Tension question from JEE Main 2012 (AIEEE)

Q22JEE Main 2012 · AIEEEEasy

Force due to Surface Tension

A thin liquid film formed between a U-shaped wire and a light slider supports a weight of 1.5×10−2 N1.5 \times 10^{-2}\text{ N} (see figure). The length of the slider is 30 cm30\text{ cm} and its weight negligible. The surface tension of the liquid film is

Figure

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Answer: (d)

  1. The film has two surfaces, each pulling the slider with TLTL: total 2TL2TL.
  2. Equilibrium: 2TL=W⇒T=W2L2TL = W \Rightarrow T = \dfrac{W}{2L}.
  3. T=1.5×10−22×0.30=0.025 N m−1T = \dfrac{1.5\times10^{-2}}{2 \times 0.30} = 0.025\text{ N m}^{-1}. So the answer is (d).
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