A thin prism P₁ with an angle 6° and made of glass of refractive index 1.54 is combined with another prism P₂ made from glass of refractive index 1.72 to produce dispersion without average deviation. The angle of prism P₂ is (a) 4.5° (b) 7.8° (c) 1.3° (d) 6°

Answer: (a). No average deviation: (μ₁ - 1)A₁ = (μ₂ - 1)A₂. 0.54 × 6° = 0.72 × A₂ A₂ = 4.5° So the answer is (a) 4.5°.

A thin prism P₁ with an angle 6° and made of glass of refractive… | JEE Main 2023 (30 Jan, Shift 2)

Q49JEE Main 2023 · 30 JAN · SHIFT 2Medium

Prism, Dispersion & Scattering

A thin prism $P_1$ with an angle $6^\circ$ and made of glass of refractive index $1.54$ is combined with another prism $P_2$ made from glass of refractive index $1.72$ to produce dispersion without average deviation. The angle of prism $P_2$ is

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Answer: (a)

No average deviation: $(\mu_1 - 1)A_1 = (\mu_2 - 1)A_2$ .
$0.54 \times 6^\circ = 0.72 \times A_2$
$A_2 = 4.5^\circ$
So the answer is (a) $4.5^\circ$ .

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