A thin prism P₁ with angle 4° made of glass having refractive index 1.54, is combined with another thin prism P₂ made of glass having refractive index 1.72 to get dispersion without deviation. The angle of the prism P₂ in degrees is (a) 1.5 (b) 16/3 (c) 3 (d) 4

Answer: (c). No deviation: (μ₁ - 1)A₁ = (μ₂ - 1)A₂. 0.54 × 4° = 0.72 × A₂ A₂ = 3° So the answer is (c) 3.

A thin prism P₁ with angle 4° made of glass having refractive index… | JEE Main 2025 (28 Jan, Shift 1)

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Prism, Dispersion & Scattering

A thin prism $P_1$ with angle $4^\circ$ made of glass having refractive index 1.54, is combined with another thin prism $P_2$ made of glass having refractive index 1.72 to get dispersion without deviation. The angle of the prism $P_2$ in degrees is

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Answer: (c)

No deviation: $(\mu_1 - 1)A_1 = (\mu_2 - 1)A_2$ .
$0.54 \times 4^\circ = 0.72 \times A_2$
$A_2 = 3^\circ$
So the answer is (c) 3.

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