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MHT CET 2024 (3 May, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2024 (3 May, Shift 2)

Q41MHT CET 2024 · 3 MAY · SHIFT 2Medium

Biot-Savart Law & Circular Coils

A thin ring of radius ' $R$ ' carries a uniformly distributed charge. The ring rotates at constant speed ' $N$ ' r.p.s. about its axis perpendicular to the plane. If ' $B$ ' is the magnetic field at the centre, the charge on the ring is ( $\mu_0 =$ permeability of free space)

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Answer: (d)

Rotating ring: $I = qN$ .
$B = \frac{\mu_0 q N}{2R} \Rightarrow q = \frac{2RB}{\mu_0 N}$
So the answer is (d) $\frac{2RB}{\mu_0 N}$ .

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