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MHT CET 2026 (15 Apr, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2026 (15 Apr, Shift 2)

Q13MHT CET 2026 · 15 APR · SHIFT 2Medium

Biot-Savart Law & Circular Coils

A thin ring of radius 'R' metre has charge 'q' coulomb uniformly spread on it. The ring rotates about its axis with a constant frequency of 'f' revolution/s. The value of magnetic induction at the centre of the ring in Wb/m ${}^{2}$ is

( $\mu_0$ = permeability of free space)

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Answer: (c)

Rotating ring acts as current $I = qf$ .
$B = \frac{\mu_0 I}{2R} = \frac{\mu_0 q f}{2R}$
So the answer is (c) $\frac{\mu_0 q f}{2R}$ .

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