Student Login

Home›Chapters›Gravitation PYQs›Newton's Law of Gravitation›Question 7

MHT CET 2023 (9 May, Shift 1) · Newton's Law of Gravitation

Newton's Law of Gravitation question from MHT CET 2023 (9 May, Shift 1)

Q7MHT CET 2023 · 9 MAY · SHIFT 1Easy

Newton's Law of Gravitation

A thin rod of length ' $L$ ' is bent in the form of a circle. Its mass is ' $M$ '. What force will act on mass ' $m$ ' placed at the centre of this circle?

( $G =$ constant of gravitation)

Show answer and solution

Answer: (a)

Every small element of the ring has an equal element diametrically opposite it at the same distance from the centre.
Their pulls on $m$ are equal and opposite, so they cancel in pairs.
So the answer is (a) zero.

Report a mistake

More questions on Newton's Law of Gravitation

A system consists of three particles each of mass ' m₁ ' placed at the corners of an…MHT CET 2023 (10 May, Shift 2)
If two identical spherical bodies of same material and dimensions are kept in contact…MHT CET 2023 (13 May, Shift 1)
Match List - I with List - II Choose the correct answer from the options given below List…NEET 2022 (Phase 1)
Two objects of equal masses placed at certain distance from each other attracts each…JEE Main 2022 (28 Jun, Shift 2)
Given below are two statements: Statement I: The law of gravitation holds good for any…JEE Main 2022 (27 Jun, Shift 1)
Three identical particles A, B and C of mass 100 kg each are placed in a straight line…JEE Main 2022 (25 Jul, Shift 1)
Find the gravitational force of attraction between the ring and sphere as shown in the…JEE Main 2021 (26 Feb, Shift 1)
A solid sphere of radius R gravitationally attracts a particle placed at 3R from its…JEE Main 2021 (25 Feb, Shift 1)