A thin spherical conducting shell of radius R has a charge q. Another… | JEE Main 2003 (AIEEE)

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Electric Potential & Equipotentials

A thin spherical conducting shell of radius $R$ has a charge $q.$ Another charge $Q$ is placed at the center of the shell. The electrostatic potential at a point $P$ at a distance $\frac{R}{2}$ from the center of the shell is

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Answer: (c)

Potential due to $Q$ at distance $\frac{R}{2}$ : $\frac{Q}{4\pi\varepsilon_0 (R/2)} = \frac{2Q}{4\pi\varepsilon_0 R}$
Point is inside the shell, so the shell contributes its surface value $\frac{q}{4\pi\varepsilon_0 R}$
$V_P = \frac{2Q}{4\pi\varepsilon_0 R} + \frac{q}{4\pi\varepsilon_0 R}$
So the answer is (c).

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