A thin uniform rod of mass ' m ' and length ' l ' is suspended from… | MHT CET 2023 (14 May, Shift 1)

Q30MHT CET 2023 · 14 MAY · SHIFT 1Medium

Rotational Kinetic Energy, Work & Power

A thin uniform rod of mass ' $m$ ' and length ' $l$ ' is suspended from one end which can oscillate in a vertical plane about the point of suspension. It is pulled to one side and then released. It passes through the equilibrium position with angular speed ' $\omega$ '. The kinetic energy while passing through mean position is

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Answer: (c)

At the mean position the rod rotates about the suspension point with $I = \frac{ml^2}{3}$ .
$KE = \frac{1}{2}I\omega^2 = \frac{1}{2}\cdot\frac{ml^2}{3}\omega^2 = \frac{ml^2\omega^2}{6}$
So the answer is (c) $\frac{ml^2\omega^2}{6}$ .

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Rotational Kinetic Energy, Work & Power question from MHT CET 2023 (14 May, Shift 1)

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