Physics Circle home Student Login

Home›Chapters›Moving Charges and Magnetism PYQs›Biot-Savart Law & Circular Coils›Question 32

NEET 2024 · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from NEET 2024

Q32NEET 2024Easy

Biot-Savart Law & Circular Coils

A tightly wound 100 turns coil of radius 10 cm10\text{ cm} carries a current of 7 A7\text{ A}. The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as 4π×10−7 SI4\pi \times 10^{-7}\text{ SI} units):

Show answer and solution

Answer: (c)

  1. B=μ0nI2rB = \frac{\mu_0 n I}{2r}
  2. B=4π×10−7×100×72×0.1=8.8×10−40.2=4.4×10−3 TB = \frac{4\pi\times10^{-7}\times 100\times 7}{2\times 0.1} = \frac{8.8\times10^{-4}}{0.2} = 4.4\times10^{-3}\text{ T}
  3. So the answer is (c) 4.4 mT.
Report a mistake

More questions on Biot-Savart Law & Circular Coils