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JEE Main 2025 (23 Jan, Shift 2) · Displacement Current, Maxwell's Equations & Production

Displacement Current, Maxwell's Equations & Production question from JEE Main 2025 (23 Jan, Shift 2)

Q5JEE Main 2025 · 23 JAN · SHIFT 2Medium

Displacement Current, Maxwell's Equations & Production

A time varying potential difference is applied between the plates of a parallel plate capacitor of capacitance 2.5 μF2.5\ \mu\text{F}. The dielectric constant of the medium between the capacitor plates is 1. It produces an instantaneous displacement current of 0.25 mA in the intervening space between the capacitor plates, the magnitude of the rate of change of the potential difference will be _________ Vs−1\text{Vs}^{-1}.

Numerical answer type. Work it out, then open the answer.

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Answer: 100

  1. Id=CdVdt⇒dVdt=IdCI_d = C\dfrac{dV}{dt} \Rightarrow \dfrac{dV}{dt} = \dfrac{I_d}{C}.
  2. dVdt=0.25×10−32.5×10−6=100\dfrac{dV}{dt} = \dfrac{0.25 \times 10^{-3}}{2.5 \times 10^{-6}} = 100.
  3. Answer: 100 V s−1^{-1}.
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