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JEE Main 2023 (25 Jan, Shift 2) · Doppler Effect

Doppler Effect question from JEE Main 2023 (25 Jan, Shift 2)

Q29JEE Main 2023 · 25 JAN · SHIFT 2Easy

Doppler Effect

A train blowing a whistle of frequency 320 Hz approaches an observer standing on the platform at a speed of 66 m/s. The frequency observed by the observer will be (given speed of sound = 330 ms $-1$ ) __________ Hz.

Numerical answer type. Work it out, then open the answer.

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Answer: 400

Source approaching: $n' = n\frac{v}{v - v_s}$ .
$n' = 320 \times \frac{330}{330 - 66} = 320 \times \frac{330}{264}$
$n' = 400$ Hz

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