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MHT CET 2026 (20 Apr, Shift 1) · Doppler Effect

Doppler Effect question from MHT CET 2026 (20 Apr, Shift 1)

Q3MHT CET 2026 · 20 APR · SHIFT 1Easy

Doppler Effect

A train is moving towards a stationary observer with speed 3434 m/s. A train sounds a whistle of frequency 450450 Hz. If the speed of sound is 340340 m/s, the frequency heard by the observer in Hz is

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Answer: (c)

  1. Source approaching: n′=nvv−vsn' = n\frac{v}{v - v_s}.
  2. n′=450×340306=450×109n' = 450 \times \frac{340}{306} = 450 \times \frac{10}{9}
  3. n′=500n' = 500 Hz. So the answer is (c) 500500.
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