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MHT CET 2024 (4 May, Shift 2) · Doppler Effect

Doppler Effect question from MHT CET 2024 (4 May, Shift 2)

Q21MHT CET 2024 · 4 MAY · SHIFT 2Easy

Doppler Effect

A train sounding a whistle of frequency 510 Hz approaches a station at 72 km/hr72\text{ km/hr}. The frequency of the note heard by an observer on the platform as the train (1) approaches the station and then (2) recedes the station are respectively (in hertz) (velocity of sound in air =320 m/s= 320\text{ m/s})

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Answer: (a)

  1. 7272 km/h =20= 20 m/s.
  2. Approaching: n1=510×320320−20=544n_1 = 510 \times \frac{320}{320 - 20} = 544 Hz
  3. Receding: n2=510×320320+20=480n_2 = 510 \times \frac{320}{320 + 20} = 480 Hz
  4. So the answer is (a) 544,480544, 480.
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