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JEE Main 2019 (10 Apr, Shift 1) · AC Generator & Transformer

AC Generator & Transformer question from JEE Main 2019 (10 Apr, Shift 1)

Q47JEE Main 2019 · 10 APR · SHIFT 1Easy

AC Generator & Transformer

A transformer consisting of 300 turns in the primary and 150 turns in the secondary gives output power of 2.2 kW. If the current in the secondary coil is 10A, then the input voltage and current in the primary coil are:

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Answer: (c)

$V_s = \dfrac{P}{I_s} = \dfrac{2200}{10} = 220\text{ V}$
$V_p = V_s\dfrac{N_p}{N_s} = 220 \times 2 = 440\text{ V}$
Ideal: $I_p = \dfrac{2200}{440} = 5\text{ A}$
So the answer is (c) 440 V and 5 A.

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