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MHT CET 2024 (10 May, Shift 2) · AC Generator & Transformer

AC Generator & Transformer question from MHT CET 2024 (10 May, Shift 2)

Q14MHT CET 2024 · 10 MAY · SHIFT 2Easy

AC Generator & Transformer

A transformer has 120 turns in the primary coil and carries 5 A current. Input power is one kilowatt. To have 560 V output, the number of turns in secondary coil will be

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Answer: (c)

  1. Primary voltage: Vp=PIp=10005=200 VV_p = \frac{P}{I_p} = \frac{1000}{5} = 200\text{ V}
  2. NsNp=VsVp⇒Ns=120×560200\frac{N_s}{N_p} = \frac{V_s}{V_p} \Rightarrow N_s = 120 \times \frac{560}{200}
  3. Ns=336N_s = 336
  4. So the answer is (c) 336.
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