A transistor is connected in common emitter circuit configuration, the collector supply voltage is 10 V and the voltage drop across a resistor of 1000 Ω in the collector circuit is 0.6 V. If the current gain factor ( β) is 24, then the base current is _____________ μ A. (Round off to the Nearest Integer) Numerical answer type. Work it out, then open the answer.

Answer: 25. IC = VR/R = (0.6)/(1000) = 0.6 mA. IB = (IC)/(β) = 0.6 × 10⁻³24 = 25 × 10⁻⁶ A. So the base current is 25 μ A.

A transistor is connected in common emitter circuit configuration… | JEE Main 2021 (27 Jul, Shift 1)

Q70JEE Main 2021 · 27 JUL · SHIFT 1Medium

Junction Transistor

A transistor is connected in common emitter circuit configuration, the collector supply voltage is 10 V and the voltage drop across a resistor of 1000 $\Omega$ in the collector circuit is 0.6 V. If the current gain factor ( $\beta$ ) is 24, then the base current is _____________ $\mu$ A. (Round off to the Nearest Integer)

Numerical answer type. Work it out, then open the answer.

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Answer: 25

$I_C = \dfrac{V_R}{R} = \dfrac{0.6}{1000} = 0.6$ mA.
$I_B = \dfrac{I_C}{\beta} = \dfrac{0.6 \times 10^{-3}}{24} = 25 \times 10^{-6}$ A.
So the base current is $25\ \mu$ A.

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