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NEET 2006 (AIPMT) · Junction Transistor

Junction Transistor question from NEET 2006 (AIPMT)

Q115NEET 2006 · AIPMTEasy

Junction Transistor

A transistor is operated in common emitter configuration at constant collector voltage VC = 1.5 V such that a change in the base current from 100 μ\muA to 150 μ\muA produces a change in the collector current from 5 mA to 10 mA. The current gain β\beta is

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Answer: (d)

  1. β=ΔICΔIB\beta = \frac{\Delta I_C}{\Delta I_B}
  2. ΔIC=5\Delta I_C = 5 mA, ΔIB=50 μ\Delta I_B = 50\,\muA =0.05= 0.05 mA
  3. β=5/0.05=100\beta = 5/0.05 = 100
  4. So the answer is (d) 100.
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