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NEET 2009 (AIPMT) · Junction Transistor

Junction Transistor question from NEET 2009 (AIPMT)

Q111NEET 2009 · AIPMTEasy

Junction Transistor

A transistor is operated in common-emitter configuration at VC = 2V such that a change in the base current from 100 μ\muA to 200 μ\muA produces a change in the collector current from 5 mA to 10 mA. The current gain is

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Answer: (c)

  1. β=ΔICΔIB\beta = \frac{\Delta I_C}{\Delta I_B}
  2. ΔIC=5\Delta I_C = 5 mA, ΔIB=100 μ\Delta I_B = 100\,\muA =0.1= 0.1 mA
  3. β=5/0.1=50\beta = 5/0.1 = 50
  4. So the answer is (c) 50.
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