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NEET 2011 (AIPMT, Prelims) · Junction Transistor

Junction Transistor question from NEET 2011 (AIPMT, Prelims)

Q108NEET 2011 · AIPMT · PRELIMSEasy

Junction Transistor

A transistor is operated in common emitter configuration at VC = 2 V such that a change in the base current from 100 μ\muA to 300 μ\muA produces a change in the collector current from 10 mA to 20 mA. The current gain is

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Answer: (a)

  1. β=ΔICΔIB\beta = \frac{\Delta I_C}{\Delta I_B}
  2. ΔIC=10\Delta I_C = 10 mA, ΔIB=200 μ\Delta I_B = 200\,\muA =0.2= 0.2 mA
  3. β=10/0.2=50\beta = 10/0.2 = 50
  4. So the answer is (a) 50.
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