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JEE Main 2022 (29 Jun, Shift 1) · Junction Transistor

Junction Transistor question from JEE Main 2022 (29 Jun, Shift 1)

Q57JEE Main 2022 · 29 JUN · SHIFT 1Medium

Junction Transistor

A transistor is used in an amplifier circuit in common emitter mode. If the base current changes by 100 μ\muA, it brings a change of 10 mA in collector current. If the load resistance is 2 kΩ\Omega and input resistance is 1 kΩ\Omega, the value of power gain is x ×\times 104. The value of x is _____________.

Numerical answer type. Work it out, then open the answer.

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Answer: 2

  1. Current gain: β=ΔICΔIB=10 mA100 μA=100\beta = \dfrac{\Delta I_C}{\Delta I_B} = \dfrac{10\ \text{mA}}{100\ \mu\text{A}} = 100
  2. Power gain: Ap=β2RLRi=104×2 kΩ1 kΩ=2×104A_p = \beta^2 \dfrac{R_L}{R_i} = 10^4 \times \dfrac{2\ \text{k}\Omega}{1\ \text{k}\Omega} = 2 \times 10^4
  3. So x=2x = 2.
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