A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μ A and the collector current changes by 1.5 mA. The load resistance is 5 k Ω. The voltage gain of the transistor will be _________. Numerical answer type. Work it out, then open the answer.

Answer: 750. Output voltage change: Δ Vo = Δ IC RL = 1.5 mA × 5 kΩ = 7.5 V Voltage gain: Av = (Δ Vo)/(Δ Vi) = (7.5 V)/(10 mV) = 750 So the voltage gain is 750.

A transistor is used in common-emitter mode in an amplifier circuit… | JEE Main 2022 (24 Jun, Shift 1)

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Junction Transistor

A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 $\mu$ A and the collector current changes by 1.5 mA. The load resistance is 5 k $\Omega$ . The voltage gain of the transistor will be _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 750

Output voltage change: $\Delta V_o = \Delta I_C R_L = 1.5\ \text{mA} \times 5\ \text{k}\Omega = 7.5\ \text{V}$
Voltage gain: $A_v = \dfrac{\Delta V_o}{\Delta V_i} = \dfrac{7.5\ \text{V}}{10\ \text{mV}} = 750$
So the voltage gain is 750.

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