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JEE Main 2025 (22 Jan, Shift 2) · Biprism, Thin Films & Other Devices

Biprism, Thin Films & Other Devices question from JEE Main 2025 (22 Jan, Shift 2)

Q10JEE Main 2025 · 22 JAN · SHIFT 2Medium

Biprism, Thin Films & Other Devices

A transparent film of refractive index, 2.0 is coated on a glass slab of refractive index, 1.45. What is the minimum thickness of transparent film to be coated for the maximum transmission of Green light of wavelength 550 nm. [Assume that the light is incident nearly perpendicular to the glass surface.]

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Answer: (b)

  1. Maximum transmission means minimum reflection.
  2. Air to film (1 to 2.0): phase change π\pi; film to glass (2.0 to 1.45): no phase change.
  3. With one π\pi shift, reflection is minimum when 2μt=mλ2\mu t = m\lambda; least t=λ2μt = \frac{\lambda}{2\mu}.
  4. t=5502×2.0=137.5 nmt = \frac{550}{2\times 2.0} = 137.5\ \text{nm}. So the answer is (b).
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