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JEE Main 2023 (10 Apr, Shift 1) · Progressive Wave Equation

Progressive Wave Equation question from JEE Main 2023 (10 Apr, Shift 1)

Q52JEE Main 2023 · 10 APR · SHIFT 1Easy

Progressive Wave Equation

A transverse harmonic wave on a string is given by

y(x,t)=5sin⁡(6t+0.003x)y(x, t) = 5\sin(6t + 0.003x)

where x and y are in cm and t in sec. The wave velocity is _______________ ms−1-1.

Numerical answer type. Work it out, then open the answer.

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Answer: 20

  1. ω=6 rad/s\omega = 6\text{ rad/s}, k=0.003 cm−1k = 0.003\text{ cm}^{-1}
  2. v=ωk=60.003=2000 cm/sv = \dfrac{\omega}{k} = \dfrac{6}{0.003} = 2000\text{ cm/s}
  3. So the answer is 20 m s−120\text{ m s}^{-1}.
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