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MHT CET 2019 (2 May, Shift 1) · Progressive Wave Equation

Progressive Wave Equation question from MHT CET 2019 (2 May, Shift 1)

Q83MHT CET 2019 · 2 MAY · SHIFT 1Medium

Progressive Wave Equation

A transverse wave is propagating on the string. The linear density of a vibrating string is 10−3 kg/m10^{-3}\text{ kg/m}. The equation of the wave is Y=0.05sin⁡(x+15t)Y = 0.05\sin(x + 15t) where xx and YY are measured in metre and time in second. The tension force in the string is

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Answer: (c)

  1. Wave speed v=ωk=151=15 m/sv = \frac{\omega}{k} = \frac{15}{1} = 15\text{ m/s}
  2. T=μv2=10−3×225=0.225 NT = \mu v^2 = 10^{-3} \times 225 = 0.225\text{ N}
  3. So the answer is (c) 0.225 N.
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