A transverse wave is propagating on the string. The linear density of vibrating string is 10⁻³ kg/m. The equation of the wave is Y = 0.05sin (x + 15t) where x and Y are in metre and time in second. The tension in the string is (a) 0.2 N (b) 0.25 N (c) 0.225 N (d) 0.325 N

Answer: (c). Wave speed v = (ω)/(k) = 15/1 = 15 m/s v = √(T/μ) ⇒ T = μ v² = 10⁻³ × 225 T = 0.225 N So the answer is (c) 0.225 N.

A transverse wave is propagating on the string. The linear density of… | MHT CET 2026 (15 May, Shift 1)

Q23MHT CET 2026 · 15 MAY · SHIFT 1Medium

Progressive Wave Equation

A transverse wave is propagating on the string. The linear density of vibrating string is $10^{-3}$ kg/m. The equation of the wave is $Y = 0.05\sin(x + 15t)$ where $x$ and $Y$ are in metre and time in second. The tension in the string is

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Answer: (c)

Wave speed $v = \frac{\omega}{k} = \frac{15}{1} = 15\text{ m/s}$
$v = \sqrt{T/\mu} \Rightarrow T = \mu v^2 = 10^{-3} \times 225$
$T = 0.225\text{ N}$
So the answer is (c) 0.225 N.

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